If cos h x = sec theta then tan h^(2) ((...

If cos h x = sec `theta` then `tan h^(2) ((x)/(2))=`

A

`tan^(2)""(theta)/(2)`

B

`cot^(2)""(theta)/(2)`

C

`-tan^(2)""(theta)/(2)`

D

`-cot^(2)""(theta)/(2)`

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The correct Answer is:

A

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