यदि P = (tan (3^(n + 1)theta) - tan thet...

यदि `P = (tan (3^(n + 1)theta) - tan theta)` एवं `Q = sum_(r = 0)^(n) (sin (3^(r)theta))/(cos (3^(r+1)theta))`, तो

P = 2Q

P = 3Q

2P = Q

3P = Q

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