A stone is thorwn vertically upwards with initial velocity of `40m//s`. Taking `g=10m//s^2`find the maximum height and total distance covered by stone

A stone is thrown vertically upwards with initial velocity of 14 m s^-1 . The maximum height it will reach is [g= 9.8 m s^-2]

A stone is thrown vertically upwards with initial velocity of 14 m s^-1 . The maximum height it will reach is [g = 9.8 m s^-2]

A body is thrown vertically upward with a velocity of 9.8 m/s. Calculate the maximum height attained by the body.(g=9.8 m/s^2)

A ball is thrown vertically upwards with a velocity of 49 m//s . Calulate (i) The maximum height to which it rises, (ii) the total time it takes to return to the surface of the earth.

A stone is thrown vertically upwards from the ground with a velocity 15 m/s. At the same instant a ball is dropped from a point directly above the stone from a height of 30 m. At what height from the ground will the stone and the ball meet and after how much time? (Use g= 10 m//s^2 for ease of calculation).

A stone thrown vertically upwards with initial velocity u reaches a height h before coming down. Show that the time taken by it to go up is the same as the time taken to come down.

A stone thrown vertically upwards with initaial velocity u reaches a height 'h' before coming down.Show that the time takes to go up is same as time taken to come down

A stone is thrown vertically upward with a velocity of 30 m//s . How high will it rise? After how much time will it return to ground ? [Take g = 10 m//s^2]

A body is projected with a velocity of 30 m/s at an angle of 30^@ with the vertical the maximum height and horizontal range are respectively

A body is projected with a vertical velocity of 30 m//s at an angle of 30^@ with the horizontal, the maximum height and horizontal range are respectively