If 80 g steam of temperature `87^@C` is released on an ice slab of temperature `O^@C` ,how much ice will melt?How much energy will be transferred to water? Given : specific heat capacity of water, c = 1 cal/g °C Latent heat of melting of ice = 80 cal/g Latent heat of vaporization of water = 540 cal/g

If 80 g steam of temperature 97^@C is released on an ice slab of temperature 0^@C ,how much ice will melt?How much energy will be transferred to water? Given : specific heat capacity of water, c = 1 cal/g °C Latent heat of melting of ice = 80 cal/g Latent heat of vaporization of water = 540 cal/g

If the mass of steam is 50g , how much ice will melt ?

Complete the analogy: Latent heat of fusion of ice : 80 cal/g :: steam:

How much steam at 100^@C will just melt 1600 g of ice at -8^@C ? (Specific heat of ice= 0.5 (cal)/g^@C , specific heat of water= 1/cal/g^@C , latent of fusion of ice = 80 cal/g , and latent heat of vaporisation of water= 540 cal/g )

1 of a steam at 100^@C melts how much ice at 0^@C ? ( Latent heat of ice=80 cal/g and latent heat of steam =540 cal/g )

A Thermally Insulated Pot Has 150 G Ice at Temperature 0°C. How Much Steam of 100°C Has to Be Mixed to It, So that Water of Temperature 50°C Will Be Obtained? Given : specific heat capacity of water, c = 1 cal/g °C Latent heat of vaporization of water = 540 cal/g Latent heat of melting of ice = 80 cal/g

How much heat will be required to convert 20g of water at 100⁰C into steam at 100⁰C ? (Specific latent heat of vaporization of water = 540 cal/g)

What does the statement, 'latent heat of fusion for ice is 80 cal/g' mean?

Find the heat absorbed by 25g of water at 100⁰C when converted into steam at the same temperature ? (Specific latent heat of vaporization of water = 540 cal/g)