Complete the analogy:
Latent heat of fusion of ice : 80 cal/g :: steam:

Latent Heat of fusion of ice is

Calculate the amount of heat absorbed by 100 g of ice to change into water of 30^@ C.(Latent heat of fusion of ice is 80 cal//g )

What does the statement, 'latent heat of fusion for ice is 80 cal/g' mean?

Find the heat required to convert 20 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the amount of heat required to convert 80 g of ice at 0⁰C into water at the same temperature . (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the quantity of heat released during the conversion of 10g of ice cold water (temperature 0⁰C ) into ice at the same temperature. (Specific latent heat of fusion of ice = 80 cal/g)

Calculate the heat absorbed if the initial temperature of 50g ice is 0^@C to change into water of the same temperature (Latent heat of fusion of ice is 80 cal//g )

How many calories of heat will be absorbed when 2kg of ice at 0⁰C melts ? (Specific latent heat of fusion of ice = 80 cal/g)

Solve the following examples / numeriacl problems: Calculate the amount of heat required to convert 5g of ice of 0⁰ C into water at 0⁰ C . (Specific latent heat of fusion of ice = 80 cal/g)

M' kg of water at 't' ^@C is divided into two parts so that one part of mass 'm' kg when converted into ice 0^@C would release enough heat to vapourise the other part, then m/M is equal to [Specific heat of water = 1 calg^-1^@C^-1 Latent heat of fusion of ice= 80 calg^-1 Latent heat of steam = 540 cal g^-1 ]