If the height of a satellite completing one revolution around the earth in T seconds is `H_1`meter,Then what would be the height of a satellite taking 2 √ 2 T second for one revolution?

Solve the following examples/numerical problems : If the height of a satellite completing one revolution around the earth in T seconds in h meters , then what would be the height of a satellite taking 2 √2 T seconds for one revolutions?

Name the following Orbits in which satellites complete one revolution in 2 to 24 hours

Satellite revolving around the earth loses some energy due to collision. What would be the effect on its velocity and distance from the centre of the earth?

If cycle wheel of radius 0.4 m completes one revolution in one second, then acceleration of the cycle is

If a cycle wheel of raduius 0.4m completes one revolution in one second, then acceleration of the cycle is

In a satellite if the time of revolution is T , then kinetic energy is proportional to

Satellite revolving around the earth at a height of 400 Km above the earth's surface has a time period of about

Obtain an expression for the period of a satellite in a circular orbit round the earth OR Show that the square of the period of revolution of satellite is directly proportional to the cube of the orbital radius. OR Show that period of the satellite revolving around the earth depends upon mass of the earth