An artificial satellite is at a height of 35780 km .from the earth's surface. What is the period of revolution of this satellite?

What is time period of polar satellite?

Suppose the satellite is revolving at a height of 35780 km above the earth's surface with velocity 3.08 km/s . How much time the satellite will take to complete one revolution around the earth ?

Suppose the orbit of a satellite is exatly 35780 km above the earth's surface. Determine the tangential velocity of the satellite.

Suppose the orbit of a satellite is exactly 35780 km above the earth's surface. Determine the tangential velocity of the satellite.

A satellite is revolving in a circular orbit very close to the surface of earth. Find the period of revolution of the satellite

A period of geostationary satellite is

Satellite revolving around the earth at a height of 400 Km above the earth's surface has a time period of about

Calculate the speed and period of revolution of a satellite orbiting at a height of 700 km above the earth's surface. Assume the orbit to be circular. Take radius of earth as 6400 km and g at the centre of earth to be 9.8 m//s^2

Obtain an expression for the period of a satellite in a circular orbit round the earth OR Show that the square of the period of revolution of satellite is directly proportional to the cube of the orbital radius. OR Show that period of the satellite revolving around the earth depends upon mass of the earth