In a `Delta ABC` with usual notations, if `(a)/(cos A)=(b)/(cos B)=(c )/(cos C)`, then the triangle is :

In Delta ABC with usual notation, (c-b cos A)/(a) is equal to

Given (b+c)/(11) = (c+a)/(12) = (a+b)/(13) for a Delta ABC with usual notation. If (cos A)/(alpha) = (cos B)/(beta) = (cos C)/(gamma) , then the ordered triad (alpha, beta, gamma) has a value:

In Delta ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos c); If b=2 'then the area of the triangle is

If any triangle ABC with usual notations prove c=a cos B + b cos A .

If cos A+cos B+cos C=(3)/(2) in a Delta ABC, then the triangle is

With usual notation,if in a triangle ABC ,(s-a)/(5)=(s-b)/(6)=(s-c)/(7), then value of cos C is-

If cos A+cos B+2cos C=2, then the sides of triangle ABC are in

In Delta ABC , with usual notations prove that : b^(2) = c^(2) +a^(2) - 2 ca cos B .