Given a family of lines a(2x +y+4) + b(x-2y-3)=0 .The number of lines belonging to the family at a distance of `sqrt(10)` from point `(2,-3)` is

Given a family of lines a(2x+y+4)+b(x-2y-1)3)=0 .The number of lines belonging to the family at a distance of sqrt(10) from point (2,-3) is

33 (d) 11 (c) (b) 3 (a) V10 Given the family of lines, a(2x y 40 b x -2y -3) 0. Among the lines of the family, the number of lines situated at a distance of v 10 from the point M (2,-3)) is (b) 1 (a) 0 (d) co o. Point (0, B) lies on or inside the triangle formed by the lines and 0, x y 2, 1, o Then o can be

Given the family of lines a(3x+4y+6)+b(x+y+2)=0 The line of the family situated at the greatest distance from the point P(2,3) has equation

Consider a family of straight lines (x+y)+lambda(2x-y+1)=0. Find the equation of straight line belonging to this family that is farthest from (1;-3)

Consider a family of straight lines (x+y)+lambda(2x-y+1)=0. Find the equation of the straight line belonging to this family that is farthest from (1,-3) .

The equation of a line of the system 2x+y+4+lambda(x-2y-3)=0 which is at a distance sqrt(10) units from point A(2,-3) is

A family of lines is given by (1+2 lambda)x+(1-lambda)y+lambda=0 being a parameter.The line belonging to this family at the maximum distance from the point (1,4) is ax+by+c=0, then find the value of (a+b+c)/(16)