A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of `1.8 m//s^(2)` will be_N.
`[g=10m//s^2]`

The mass of lift is 500 kg. When it ascends with an acceleration of 2m//s^(2) ,the tension in the cable will be [g=10m//s^(2)]

A man standing in a lift holds a spring balance with a load of 5 kg suspended from it What would be the reading of the balance when the lift is descending with an acceleration of 3.8 m//s^(2) .

The time period of a simple pendulum inside a stationary lift is sqrt(5) s. What will be the time period when the lift moves upward with an acceleration (g)/(4) ?

When a man holding spring balance in stationary lift then it's reading is 60 kg . Now if lift starts descends with constant acceleration 1.8 m/ s^(2) then what is the new reading of spring balance in newton (take g =10 m/ s^(2) )

A person of mass 50 kg stands on a weighing scale on a lift . If the lift is descending with a downward acceleration of 9ms^(-2) what would be the reading of the weighing scale? (g =10ms^(-2)) .

A body of mass 50kg is put on a spring weighing machine in a lift What is the reading of the machine when (i) Lift ascends with a unifrom velocity of 10m//s (ii)descends with an acceleration of 5m//s^(2) ? Take of = 10m//s^(2) .

When a liftman takes 5 persons in a lift, the totla mass of the lilft and the 5 persons becomes 800 kg. What is the tension in the supporting cable, if the lift ascends with an acceleration of 2m//s^(2) ? (g=10m//s^(2)

A man of mass 60 kg is standing on a spring balance inside a lift. If the lift falls downwards, then the reading of the spring balance will be:-