The intensities of two sources are`I` and `9I` respectively, If the phase difference between the waves emitted by is `pi` then the resultant intensity at the point of observation will be-

The intensities of two sources are I a nd 9I respectively,If the phase difference between the waves emitted by then is pi then the resultant intensity at the point of observation will be-

The intensities of two light sources are I and 91 .If the phase difference between the waves is pi then resultant intensity will be :-

For minimum intensity the phase difference between the two waves is

The intensity of interference waves in an interference pattern is same as I_(0) . The resultant intensity at the point of observation will be

Two light sources with intensity I_(0) each interfere in a medium where phase difference between them us (pi)/2 . Resultant intensity at the point would be.

Two coherent sources each emitting light of intensity I_(0) Interfere, in a medium at a point, where phase different between them is (2pi)/3 . Then, the resultant intensity at that point would be.

Assertion: Two identical waves due to two coherent sources interfere at a point with a phase difference of (2pi)/3 , then the resultant intensity at this point is equal to the individual intensity of the sources. Reason: A phase difference of (2pi)/3 is equivalent to a path difference of lambda/3 .

Interference fringes are produced on a screen by using two light sources of intensities / and 9/. The phase difference between the beams pi/2 is at point P and pi at point Q on the screen. The difference between the resultant intensities at point P and Q is