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If conductivity of 0.1 mol/dm^3 solution...

If conductivity of `0.1` `mol`/`dm^3` solution of KCl is `1.3 * 10^(-2) S cm^(-1)` at 298 K then its molar conductivity will be

A

`130` `S cm^(2)`/`mol`

B

`250` `S cm^(2)`/`mol`

C

`75` `S cm^(2)`/`mol`

D

`182` `S cm^(2)`/`mol`

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