Heat of combustion of carbon monoxide is -283.5 kJ/mole. The heat released when 55 g of carbon dioxide formed from carbon monoxide is

Options

A. 283.5 kJ
B. 324.2 kJ
C. 354.4 kJ
D. 385.5 kJ

Answer

To solve the problem of finding the heat released when 55 g of carbon dioxide (CO2) is formed from carbon monoxide (CO), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
The combustion of carbon monoxide can be represented by the following reaction:
\[ 2 \text{CO} + \text{O}_2 \rightarrow 2 \text{CO}_2 \]
From this reaction, we see that 1 mole of CO produces 1 mole of CO2.

2. **Calculate the Moles of CO2**:
To find the number of moles of CO2 produced from 55 g of CO2, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} \]
The molar mass of CO2 is:
\[ \text{Molar mass of CO2} = 12 \, (\text{C}) + 16 \times 2 \, (\text{O}) = 44 \, \text{g/mol} \]
Now, we can calculate the moles of CO2:
\[ \text{Number of moles of CO2} = \frac{55 \, \text{g}}{44 \, \text{g/mol}} \approx 1.25 \, \text{moles} \]

3. **Relate Moles of CO to Heat Released**:
The heat of combustion of CO is given as -283.5 kJ/mole. Since 1 mole of CO produces 1 mole of CO2, the heat released for 1 mole of CO is -283.5 kJ.

4. **Calculate Heat Released for 1.25 Moles of CO2**:
Since we have 1.25 moles of CO2, the heat released can be calculated as:
\[ \text{Heat released} = \text{Number of moles of CO2} \times \text{Heat of combustion per mole} \]
\[ \text{Heat released} = 1.25 \, \text{moles} \times -283.5 \, \text{kJ/mole} = -354.375 \, \text{kJ} \]

5. **Final Answer**:
The heat released when 55 g of carbon dioxide is formed from carbon monoxide is approximately:
\[ \text{Heat released} \approx -354.38 \, \text{kJ} \]