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Compressibility factor under critical st...

Compressibility factor under critical state of a gas is

A

`frac{5}{8]`

B

`frac{8}{3}`

C

`frac{3}{8R}`

D

`frac{3}{8}`

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The correct Answer is:
To find the compressibility factor (Z) under the critical state of a gas, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Compressibility Factor (Z)**: The compressibility factor (Z) is defined as: \[ Z = \frac{PV}{nRT} \] where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature. 2. **Using Critical Constants**: Under critical conditions, we need to use the critical constants: - \( P_c \) (critical pressure) - \( V_c \) (critical volume) - \( T_c \) (critical temperature) 3. **Substituting Critical Values**: The critical constants can be expressed in terms of the parameters a and b (from the van der Waals equation): - \( T_c = \frac{8a}{27bR} \) - \( V_c = 3b \) - \( P_c = \frac{8a}{27b^2} \) 4. **Substituting into the Compressibility Factor Formula**: Now, substituting these values into the formula for Z: \[ Z = \frac{P_c V_c}{R T_c} \] 5. **Calculating Z**: Substitute \( P_c \), \( V_c \), and \( T_c \) into the equation: \[ Z = \frac{\left(\frac{8a}{27b^2}\right) \cdot (3b)}{R \cdot \left(\frac{8a}{27bR}\right)} \] 6. **Simplifying the Expression**: Simplifying the above expression: \[ Z = \frac{\frac{24ab}{27b^2}}{\frac{8a}{27b}} = \frac{24ab \cdot 27b}{27b^2 \cdot 8a} \] Cancelling out common terms: \[ Z = \frac{24}{8} = 3 \] 7. **Final Result**: Therefore, the compressibility factor under critical state of a gas is: \[ Z = \frac{3}{8} \]
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