Solubility product of Ba(OH)2 is 5.01×10...

Solubility product of `Ba(OH)_2 is 5.01×10^(-7)`,pOH of saturated solution of `Ba(OH)_2` is

A

`10`

B

`12`

C

`4`

D

`2`

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The correct Answer is:

D

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