Home
Class 12
PHYSICS
Electric field and magnetic field in a r...

Electric field and magnetic field in a region of space are given by`(Ē= E_0 hat j)`. and `(barB = B_0 hat j)`. A charge particle is released at origin with velocity `(bar v = v_0 hat k)` then path of particle is

A

Straight line

B

Helical with uniform pitch

C

Circular path

D

Helical with increasing pitch

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

Electric field and magnetic field in a region of space are given by vec E = E_(0) hat I " and " vec B = - B_(0) hat k , respectively. A positively charged particle (+q) is released from rest at the origin. When the particle reaches a point P(x, y, z) , then it attains kinetic energy K that is equal to

A positively charged particle of mass m and charge q is projected on a rough horizontal x-y plane surface with z-axis in the vertically upward direction. Both electric and magnetic fields are acting in the region and given by vec E = - E_0 hat k and vec B= -B_0 hat k , respectively. The particle enters into the field at (a_0, 0, 0) with velocity vec v = v_0 hat j . The particle starts moving in some curved path on the plane. If the coefficient of friction between the particle and the plane is mu . Then calculate the (a) time when the particle will come to rest (b) distance travelled by the particle when it comes to rest.

Electric field strength bar(E)=E_(0)hat(i) and bar(B)=B_(0)hat(i) exists in a region. A charge is projected with a velocity bar(v)=v_(0)hat(j) at origin , then

A particle of charge q and mass m released from origin with velocity vec(v) = v_(0) hat(i) into a region of uniform electric and magnetic fields parallel to y-axis. i.e., vec(E) = E_(0) hat(j) and vec(B) = B_(0) hat(j) . Find out the position of the particle as a functions of time Strategy : Here vec(E) || vec(B) The electric field accelerates the particle in y-direction i.e., component of velocity goes on increasing with acceleration a_(y) = (F_(y))/(m) = (F_(e))/(m) = (qE_(0))/(m) The magnetic field rotates the particle in a circle in x-z plane (perpendicular to magnetic field) The resultant path of the particle is a helix with increasing pitch. Velocity of the particle at time t would be vec(v) (t) = v_(x) hat(i) + v_(y) hat(j) + v_(z) hat(k)

Electric and magnetic field are directed as E_(0) hat(i) and B_(0) hat(k) , a particle of mass m and charge + q is released from position (0,2,0) from rest. The velocity of that particle at (x,5,0) is (5 hat(i) + 12 hat(j)) the value of x will be

There exists a uniform magnetic field vec(B) = +B_(0) hat(k) " for " x gt 0 and vec(B) = 0 for all x lt 0 . A charged particle placed at (0, -a,0) is given an initial velocity vec(v) = v_(0) hat(i) . What is the magnitude and nature of charge on the particle such that it crosses through the origin ? Strategy: When the charge is projected perpendicular to a uniform magnetic field, it follows a circular path. In this case, the force acting on it will be directed either towards +y-axis. or y-axis. It is given that it crosses point O. Thus, the force at (0, -a, 0) must be towards y-axis

A particle of charge q and mass m starts moving from the origin under the action of an electric field vec E = E_0 hat i and vec B = B_0 hat i with a velocity vec v = v_0 hat j . The speed of the particle will become 2v_0 after a time.

A particle ( mass = m and charge = q ) is moving in a region in which there exists a uniform electric field E vec( i ) and a uniform magnetic field B hat (k) . At t = 0 , the particle is at ( 0,a ) and is moving with v hat(i) . After some time, the particle is located at ( 2a, 0 ) and has a velocity - 2 v hat( j ) , then which of the following is true ?