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If force on a particle vecF = (Sin at)ha...

If force on a particle `vecF = (Sin at)hati + (cos at)hatj` and displacement `vecS = sin(frac{at}{3}hati) + cos(frac{at}{3})hatj` are functions of time (t) then value of t at which they are perpendicular for first time is (a is positive constant and t>0)

A

`t = frac{pi}{2]`

B

`t=frac{3pi}{2a}`

C

`t = frac{3pi}{4a}`

D

`t = frac{pi}{3}`

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The correct Answer is:
c
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