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A 50 kg man stuck in flood is being lift...

A 50 kg man stuck in flood is being lifted vertically by an army helicopter with the help of light rope which can bear a maximum tension of 70 kg-wt. The maximum acceleration with which helicopter can rise so that rope does not breaks is `(g = 9.8 ms^(-2))`

A

4.00`ms^-2`

B

`3.92ms^-2`

C

`3.52ms^-2`

D

`3.00ms^-2`

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Knowledge Check

  • A monkey of mass 30 kg climbs a rope which can withstand a maximum tension of 360 N. The maximum acceleration which this rope can tolerate for the climbing of monkey is: (g=10m//s^(2))

    A
    `2 m//s^(2)`
    B
    `3 m//s^(2)`
    C
    `4 m//s^(2)`
    D
    `5 m//s^(2)`

  • A string tied on a roof can bear a maximum tension of 50 kg wt. The minimum acceleration that can be acquired by a man of 98 kg to descend will be [take g = 9*8 m/s^(2) ]

    A
    `9*8 m/s^(2)`
    B
    `4*9m/s^(2)`
    C
    `4*8 m/s^(2)`
    D
    `5 m/s^(2)`

  • A body of mass 60 kg is holding a vertical rope . The rope can break when a mass of 75 kg is suspended from it. The maximum acceleration with which the boy can climb the rope without breaking it is : ( g = 10 m//s^(2))

    A
    `2.5 m//s^(2)`
    B
    `5.0 m//s^(2)`
    C
    ` 7.5 m//s^(2)`
    D
    `22.5m//s^(2)`

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