For hetrozygous tall plant of pea undergoing selfing, what would be the sum of phenotype and genotypes obtained in F_1 generation?

Options

A. 2
B. 5
C. 3
D. 4

Answer

To solve the problem of determining the sum of phenotypes and genotypes obtained in the F1 generation from a heterozygous tall pea plant undergoing selfing, we can follow these steps:

### Step 1: Identify the Genotype of the Parent
The heterozygous tall plant has the genotype Tt, where:
- T = dominant allele for tallness
- t = recessive allele for dwarfism

### Step 2: Set Up the Punnett Square
To find the possible genotypes in the F1 generation, we set up a Punnett square for the selfing of two Tt plants:

```
T t
______________
T | TT | Tt |
______________
t | Tt | tt |
______________
```

### Step 3: Determine the Genotypes from the Punnett Square
From the Punnett square, we can see the following genotypes:
- TT (homozygous tall)
- Tt (heterozygous tall)
- Tt (heterozygous tall)
- tt (homozygous dwarf)

### Step 4: Count the Genotypes
The genotypes obtained are:
- 1 TT
- 2 Tt
- 1 tt

So, the total number of genotypes is 4:
- 1 TT
- 2 Tt
- 1 tt

### Step 5: Determine the Phenotypes
Now, we count the phenotypes based on the genotypes:
- TT and Tt are both tall (dominant phenotype)
- tt is dwarf (recessive phenotype)

Thus, the phenotypes are:
- 3 tall (1 TT + 2 Tt)
- 1 dwarf (1 tt)

### Step 6: Count the Phenotypes
The total number of phenotypes is:
- 3 tall
- 1 dwarf

So, the total number of phenotypes is 4.

### Step 7: Sum of Phenotypes and Genotypes
Now, we add the total number of phenotypes and genotypes:
- Total phenotypes = 4
- Total genotypes = 3

Sum = 4 (phenotypes) + 4 (genotypes) = 8

### Final Answer
The sum of phenotypes and genotypes obtained in the F1 generation is **8**.

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