Percentage of inflated pod, wrinkled seed and axial flower obtained in F_2 generation of Mendel's monohybrid cross are respectively

Options

A. 75%, 75%, 25%
B. 25%, 50%,75%
C. 75%,50%,25%
D. 75%,25%,75%

Answer

To solve the question regarding the percentage of inflated pod, wrinkled seed, and axial flower obtained in the F2 generation of Mendel's monohybrid cross, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Traits**:
- In Mendel's experiments, he studied various traits in pea plants. The traits mentioned in the question are:
- Inflated Pod (dominant)
- Wrinkled Seed (recessive)
- Axial Flower (dominant)

2. **Identify Dominant and Recessive Traits**:
- Inflated Pod is a dominant trait, represented as 'I'.
- Wrinkled Seed is a recessive trait, represented as 'w'.
- Axial Flower is a dominant trait, represented as 'A'.

3. **Monohybrid Cross Ratios**:
- In a monohybrid cross, the typical phenotypic ratio in the F2 generation is 3:1 for dominant to recessive traits.
- This means that for every 4 offspring, 3 will exhibit the dominant trait and 1 will exhibit the recessive trait.

4. **Calculate Percentages**:
- For the dominant traits (Inflated Pod and Axial Flower):
- Percentage of Inflated Pod = (3 out of 4) * 100 = 75%
- Percentage of Axial Flower = (3 out of 4) * 100 = 75%
- For the recessive trait (Wrinkled Seed):
- Percentage of Wrinkled Seed = (1 out of 4) * 100 = 25%

5. **Final Answer**:
- The percentages of the traits in the F2 generation are:
- Inflated Pod: 75%
- Wrinkled Seed: 25%
- Axial Flower: 75%

### Summary of the Answer:
- The percentages are:
- Inflated Pod: 75%
- Wrinkled Seed: 25%
- Axial Flower: 75%