If the frequency of occurrence of dominant allele A id p and that of recessive allele a is q.Then according to Hardy Weinberg law q is equal to.

Options

A. `1+p`
B. `1-p^2-2pq`
C. `1-p`
D. Both (1) and (2)

Answer

To solve the question regarding the Hardy-Weinberg law and the relationship between the frequencies of dominant and recessive alleles, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Allele Frequencies**:
- Let the frequency of the dominant allele \( A \) be denoted as \( p \).
- Let the frequency of the recessive allele \( a \) be denoted as \( q \).

2. **Hardy-Weinberg Principle**:
- According to the Hardy-Weinberg law, the sum of the frequencies of the alleles in a population must equal 1. This can be expressed mathematically as:
\[ p + q = 1 \]

3. **Rearranging the Equation**:
- To find the value of \( q \), we can rearrange the equation:
\[ q = 1 - p \]

4. **Conclusion**:
- Therefore, according to the Hardy-Weinberg law, the frequency of the recessive allele \( a \) (denoted as \( q \)) is equal to \( 1 - p \).

### Final Answer:
\[ q = 1 - p \]

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