The sum of father's age and twice the age of his son is 70. If we double the age of the father and add it to the age of his son the sum is 95. Find their present ages.

Father is four times as old as his son today. The: age of father at the birth of his son was 30 years. Find their Present ages.

When the son will be as old as his father today, the sum of their ages then will be 126, when the father was as old as his son is today, the sum of their ages then was 38. Find their present ages.

The ratio of the present ages of mother and son is 12:5 The mother 's age at the time of birthe of the son was 21 years. Find the present ages.

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son. Write their present ages.

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son. Write mother's age six years before.

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son. Form a quadratic equation from the given condition and solve it.

Vivek is 5 years elder to Kishor. The sum of the reciprocal of their ages is 1/6. Find their present ages.

Sum of the present ages of Manish and Savita is 31. Manish’s age 3 years ago was 4 times the age of Savita. Find their present ages.

Vivek is older than Kishor by 5 years. The sum of the reciprocals of their ages is 1/6 . Find their present ages.