Moment of inertia of a thin ring of Radius `R` about an axis passing through any diameter is `(1/2MR^2)`.
What is the radius of gyration of the ring about an axis passing through any diameter?

The moment of inertia of a thin ring of Radius R about an axis passing through any diameter is (1/2MR^2) A thin metal ring has a diameter 0.20cm and mass 1kg .Calculate its moment of inertia about an axis passing through any tangent.

What is the radius of gyration of the ring about an axis passing through its centre mass and perpendicular to its plane?

The moment of intertidal of a thin rod of mass M and length l about an axis perpendicular to the rod at its midpoint is M_l^2/12 . what is the radius of gyration in the above case?

a) Find the moment of inertia of a sphere about a tangent to the sphere, given the moment of inertia of the sphere about any of its diameters to be (2MR^2)/5 , where M is the mass of the sphere and R is the radius of the sphere. b) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be MR^2/4 , find its moment of inertia about an axis normal to the disc and passing through a point on its edge.