The moment of inertia of a thin ring of Radius `R` about an axis passing through any diameter is `(1/2MR^2)`
A thin metal ring has a diameter `0.20cm` and mass `1kg`.Calculate its moment of inertia about an axis passing through any tangent.

Moment of inertia of a thin ring of Radius R about an axis passing through any diameter is (1/2MR^2) . What is the radius of gyration of the ring about an axis passing through any diameter?

Moment of inertia plays the same roll in rotational motion as mass in linear motion. The moment of inertia of a body changes when the axis of rotation changes.If the moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is (MR^2)/2) ( M is the mass of the disc and R its radius). Determine its moment of inertia about a diameter and about a tangent.

Moment of inertia of a ring about an axis passing through the center is MR^2 . The moment of inertia about a diameter can be found using the perpendicular axis theorem.Obtain the expression for the moment of inertia of a ring about its diameter.

What is the equation of the moment of inertia of a disc about an axis passing through its center and measured perpendicular to its plane?