A thin circular ring is rotating about an axis perpendicular to its plane. State the theorem which will help you to find the moment of inertia about its diameter.

A thin circular ring is rotating about an axis passing through its center and perpendicular to its plane. Find the moment of inertia of the ring about its diameter.

Consider moment of inertia of a uniform thin circular disc about a diametrical axis of the disc. There is a theorem which helps to find the moment of inertia of the disc about another axis parallel to this axis. Give the statement of this theorem.

The moment of intertidal of a thin rod of mass M and length l about an axis perpendicular to the rod at its midpoint is M_l^2/12 . A student has to find the moment of of inertia of the above rod about an axis(AB) perpendicular to the rod and passing through one end of the rod. Name and state the law used for this case.

Moment of inertia plays the same roll in rotational motion as mass in linear motion. The moment of inertia of a body changes when the axis of rotation changes.If the moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is (MR^2)/2) ( M is the mass of the disc and R its radius). Determine its moment of inertia about a diameter and about a tangent.

The moment of intertidal of a thin rod of mass M and length l about an axis perpendicular to the rod at its midpoint is M_l^2/12 . Using the theorem, find the moment of the rod about AB.

Moment of inertia of a ring about an axis passing through the center is MR^2 . The moment of inertia about a diameter can be found using the perpendicular axis theorem.Obtain the expression for the moment of inertia of a ring about its diameter.