Moment of inertia of a ring about an axis passing through the center is `MR^2`. The moment of inertia about a diameter can be found using the perpendicular axis theorem.Obtain the expression for the moment of inertia of a ring about its diameter.

A thin circular ring is rotating about an axis passing through its center and perpendicular to its plane. Find the moment of inertia of the ring about its diameter.

Moment of inertia of a thin ring of Radius R about an axis passing through any diameter is (1/2MR^2) . What is the radius of gyration of the ring about an axis passing through any diameter?

The moment of inertia of a thin ring of Radius R about an axis passing through any diameter is (1/2MR^2) A thin metal ring has a diameter 0.20cm and mass 1kg .Calculate its moment of inertia about an axis passing through any tangent.

Moment of inertia in rotational motion is analogus to mass in linear motion.The moment of inertia of a circular disc about an axis perpendicular to the plane, at the centre is given by.

Moment of inertia about a diameter of a ring is (I_O= (MR^2)/2) Draw a diagram and find the moment of inertia about a tangent, parallel to the diameter of the ring.

A thin circular ring is rotating about an axis perpendicular to its plane. State the theorem which will help you to find the moment of inertia about its diameter.

a) Find the moment of inertia of a sphere about a tangent to the sphere, given the moment of inertia of the sphere about any of its diameters to be (2MR^2)/5 , where M is the mass of the sphere and R is the radius of the sphere. b) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be MR^2/4 , find its moment of inertia about an axis normal to the disc and passing through a point on its edge.

Moment of inertia plays the same roll in rotational motion as mass in linear motion. The moment of inertia of a body changes when the axis of rotation changes.If the moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is (MR^2)/2) ( M is the mass of the disc and R its radius). Determine its moment of inertia about a diameter and about a tangent.