What is the moment of inertia of a disc about one of its diameter?

A thin circular ring is rotating about an axis passing through its center and perpendicular to its plane. Find the moment of inertia of the ring about its diameter.

a) Find the moment of inertia of a sphere about a tangent to the sphere, given the moment of inertia of the sphere about any of its diameters to be (2MR^2)/5 , where M is the mass of the sphere and R is the radius of the sphere. b) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be MR^2/4 , find its moment of inertia about an axis normal to the disc and passing through a point on its edge.

Moment of inertia of a ring about an axis passing through the center is MR^2 . The moment of inertia about a diameter can be found using the perpendicular axis theorem.Obtain the expression for the moment of inertia of a ring about its diameter.

What is the equation of the moment of inertia of a disc about an axis passing through its center and measured perpendicular to its plane?

Consider moment of inertia of a uniform thin circular disc about a diametrical axis of the disc. There is a theorem which helps to find the moment of inertia of the disc about another axis parallel to this axis. Give the statement of this theorem.

Moment of inertia plays the same roll in rotational motion as mass in linear motion. The moment of inertia of a body changes when the axis of rotation changes.If the moment of inertia of a disc about an axis passing through its centre and perpendicular to its plane is (MR^2)/2) ( M is the mass of the disc and R its radius). Determine its moment of inertia about a diameter and about a tangent.