Time period of a particle in simple harmonic motion (SHM) depends on the force constant `K` and mass `m` of the particle.
A man with his wristwatch on his hands falls from the top of a tower.Does the watch give the correct time during the free fall?Why?

A particle executes a simple harmonic motion with a period 2 seconds, starting from its equilibrium at time t=0 . Find the minimum time in which it is displaced by half the amplitude.

The motion that repeat themselves are called periodic motions but for a simple harmonic motion, the force must be proportional to the displacement and it is directed towards the centre of motion. A particle executes a SHM of amplitude 'a'. At what distance from the mean position is its kinetic energy equal to its potential energy?

Time period of a particle in SHM is T=2pisqrt(m/k) . A simple pendulum executes SHM approximately. Why then is the time period of pendulum is independent of mass?

The motion represented by the equation y(t)=A cos(omegat+phi) is called simple harmonic motion (SHM). The displacement of y (in cm) of an oscillating particle varies with time t (in sec) according to the equation. y=2cos(0.5pit+pi/3) . Find the amplitude and period of the particle.