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One gram atom of an element contains 6.0...

One gram atom of an element contains `6.023xx10^23` atoms.Define mole and Avogadro number.

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Choose the incorrect statement from the following. a) 1 mole Hydrogen atom contains 6.022xx10^23 atoms. b) 1 mole oxygen gas contains 2xx6.022xx10^23 atoms. c) Mass of 1 mole of chlorine is 35.5 g. d) Mass of 0.5 mole of water is 18g. e) 1 mole of nitrogen gas contains 22.4L volume at any state. (Hint: Atomic mass H-1, 0-16, 1-35.5,N=14)

MAXIMUM PUBLICATION-SOME BASIC CONCEPTS OF CHEMISTRY-EXAMPLE
  1. One gram atom of an element contains 6.023xx10^23 atoms. Find the numb...

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  2. One gram atom of an element contains 6.023xx10^23 atoms. Which is heav...

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  3. One gram atom of an element contains 6.023xx10^23 atoms.Define mole an...

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  4. Classify the following as homogeneous and heterogeneous mixtures. Air,...

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  5. State and explain law of multiple proportions with example.

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  6. One mole of an ideal gas occupies 22.4L at STP. Calculate the mass of ...

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  7. One mole of an ideal gas occupies 22.4L at STP. Calculate the number o...

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  8. 21 g of nitrogen gas is mixed with 5g of hydrogen gas to yield ammonia...

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  9. When two elements combine to form more than one compound the different...

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  10. When two elements combine to form more than one compound the different...

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  11. A compound contains 80% of carbon and 20% hydrogen. If the molecular m...

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  12. A compound contains 4.07% of hydrogen, 24.27% of carbon and 71.65% of ...

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  13. Nitrogen forms various oxides. Identify the law of chemical combinatio...

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  14. Which of the following weighs more? 1 mole of glucose, 4 moles of oxyg...

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  15. 3 g of H2 is mixed with 29 g of O2 to yield water. Which is the limite...

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  16. 3 g of H2 is mixed with 29 g of O2 to yield water. Calculate the maxim...

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  17. 3 g of H2 is mixed with 29 g of O2 to yield water. Calculate the amoun...

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  18. Calculate the mass of oxygen required for the complete burning of 2 g ...

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  19. Calculate the molar mass of CO2.

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  20. Calculate the molar mass of CH4.

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