OABCDEFG is acube with edges of length 8 units and axes are shown. L,M,N are midpoints of the edges FG, GD, GB respectively.
Find p.v's of F,B,D and G.

OABCDEFG is acube with edges of length 8 units and axes are shown. L,M,N are midpoints of the edges FG, GD, GB respectively. Find the p.v's of L,M,N.

OABCDEFG is acube with edges of length 8 units and axes are shown. L,M,N are midpoints of the edges FG, GD, GB respectively. Show that the angle between the main diagonis is theta=cos^-1(1/3)

OABCDEFG is acube with edges of length 8 units and axes are shown. L,M,N are midpoints of the edges FG, GD, GB respectively. Show that vec(LM)+vec(MN)+vec(NL)=0

The diagram of a cubic crystal whose molecular mass=M, edge length=a, density=P , is given below. N is the Avogrado number. From the above given details find the mass of this cube and also the mass of N particles?

Density of a unit cell is the same as the density of the substance. So, if the density of the substance is known, we can calculate the number of atoms or dimensions of the unit cell. The density of the unit cell is related to its formula mass (M), number of atoms per unit cell (z), edge length (a in cm), and Avogadro's constant N_(A) , as rho=(zxxM)/(a^(3)xxN_(A)) Q. An element X crystallizes in a structure having an fcc unit cell of an edge 100 pm. if 24 g of the element contains 24xx10^(23) atoms, the density is

Density of a unit cell is the same as the density of the substance. So, if the density of the substance is known, we can calculate the number of atoms or dimensions of the unit cell. The density of the unit cell is related to its formula mass (M), number of atoms per unit cell (z), edge length (a in cm), and Avogadro's constant N_(A) , as rho=(zxxM)/(a^(3)xxN_(A)) Q. A metal A (atomic mass=60) has a body-centred cubic crystal structure. the density of the metal is 4.2 g cm^(-3) . the volume of unit cell is