Larger the size of an ion, more is its ionic conductance

The length of a wire is doubled. Its conductance will

The limiting molar condcutance of sodium chloride, potassium chloride and potassium bromide are 126.45, 149.86 and 151.92 ohm^-1 cm^2 mol^-1 respectively. Calculate the limiting molar ionic conductance of Na^+ given that limiting molar ionic conductance of Br^- ion is 76.34 ohm^-1 cm^2 mol^-1 .

The limiting equivalent conductivity of NaCl, KCl and KBr are 126.5,150.0 and 151.5 S cm^(2) eq^(-1) , respectively. The limiting equivalent ionic conductance for Br^(-) is 78 S cm^(2) eq^(-1) . The limiting equivalent ionic conductance for Na^(+) ions would be :

A coordination compound has the formula CoCl_3 .4NH_3 . It precipitates silver ions as AgCl and its molar conductance corresponds to a total of two ions. Deduce its structural formula and name the complex.

A coordination compound has the formula CoCl_3 .4NH_3 . It precipitates silver ions as AgCl and its molar conductance corresponds to a total of two ions. Replace ammonia molecules by two molecules of ethylenediamine and discuss isomerism in the resulting complex ion.

Calculate the molar conductance at infinite dilution (lambda^om) of CaCl_2 ,given that molar ionic conductance for lambda^om(Ca^(2+)) 119.5 and Cl- (76.3) S cm^2mol^(-1)

Calculate the molar conductance of a solution of MgCl_2 at infinite dilution, gievn that the molar ionic conductance of lambda^o (Mg^(2+))=126.1S cm^2mol^(-1) and lambda^o (Cl^(-))=56.3 Scm^2mol^(-1) .

The conductivity of a saturated solution of AgBr at 25^@C is 8.5xx10^-7 S cm^-1 . If the limiting molar ionic conductance of Ag^+ and Br^- ions are 62 and 78 S cm^2 mol^-1 , then calculate the solubility product of AgBr.