At what distance on the axis, from the centre for circular current carrying coil of radius r, the magnetic field becomes 1/8 th of the magnetic field at centre?

The magnetic field at the centre of the current carrying coil

The magnetic field at the centre of current carrying coil is

Why is magnetic field maximum at the centre of a current-carrying coil?

The magnetic field on the axis of a circular current carrying conductor of radius r at a distance r from centre is B_(a) and the magnetic field at its centre is B_(c ) . The value of B_(a) : B_(c ) is

A circular loop of radius R, carries current. At what distance from the centre of the loop along the axis, the magnetic field intensity becomes half of its magnetic field intensity at the centre. Given: root(3)(4) = 1.5874 & sqrt(0.5874) = 0.7664 .

The ratio of magnetic fields on the axis of a cricular current cerrying coil of radius a to the magnetic field at its centre lying on the periphery of the surface of the sphere will be .

What will be magnetic field at centre of current carrying circular loop of radius R?

The magnetic field at the centre of a circular current carrying coil of radius r is B^(e ) . The magnetic on its axis at a distance r from the centre is B_(a) . The value of B_(e) : B_(a) will be :

What happens to the magnetic field at the centre of a circular current carrying coil if we double the radius of the coil keeping the current unchanged?