Initially `K_(1)` is closed, now if `K_(2)` is also closed, find heat dissipated in the resistances of connecting wires

Find heat dissipated in the circuit after switch S in closed. C = 2 muF .

Four identical capacitors are connected with a battery of voltage V and two switches k_(1) and k_(2) as shown in the figure below. Initially, k_(1) is closed, now if k_(2) is also closed, find the heat loss.

The reading of an ammeter in the circuit (i) I when key K_(1) closed key K_(2) is open (ii) I//2 when both keys K_(1) and K_(2) are closed Find the expression for the resistance of X in terms of the resistances of R and S

In the circuit shown in Fig, instially K_(1) is closed and K_(2) is open . What are the charges on each capacitor. Then K_(1) was opened and K_(2) was closed (order is important). What will be the charge on each capacitor now ? [C = 1muF]

The capacitor 'C' is initially unchanged. Switch S_(1) is closed for a long time while S_(2) remains open. Now at t = 0 S_(2) is closed while S_(1) is opened. All the batteries are ideal and connecting wires are resistanceless

In the circuit shown in figure , initially key K_(1) is closed and key K_(2) is open. Then K_(1) is opened and K_(2) is closed (order is important). [Take Q_(1)^(') and Q_(2)^(') as charges on C_(1) and C_(2) and V_(1) and V_(2) as voltage respectively]. Then

In given circuit initially switch S_(1) is closed for long time and then opened and now S_(2) is closed. The total energy dissipated in 4 Omega resistor is equal to :-