The two blocks A and B of equal mass are initially in contact when released from rest on the inclined plane. The coefficients of friction between the inclined plane and A and B are `mu_(1)` and `mu_(2)` respectiely. Friction is not sufficient to prevent slipping.

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

When a body slides down an inclined plane with coefficient of friction as mu_(k) , then its acceleration is given by .

The coefficient of friction between m_(2) and inclined plane is mu (shown in the figure). If (m_(1))/(m_(2))=sin theta then

In the figure shown, if friction coefficient of block 1 kg and 2kg with inclined plane is mu_(1) = 0.5 and mu_(2) = 0.4 respectively, then

A solid cylinder of mass m and radius r is rolling on a rough inclined plane of inclination theta . The coefficient of friction between the cylinder and incline is mu . Then.

A small blockofmass 'm' is released from rest at the top of a rough inclined plane as shown The coefficient of friction between the block and inclined plane is 'mu' Using work-energy theorem, find the speed of block as it passes the lowest point.

A block of mass m is lying on an inclined plane. The coefficient of friction between the plane and the block is mu . The force (F_(1)) required to move the block up the inclined plane will be:-

Two blocks are in contect moving on an inclined plane of inclination alpha with the horizontal. The masses of the blocks are equal to m_(1) and m_(2) and the coefficients of friction between the inclined plane and the blocks are equal to mu_(1) and mu_(2) (mu_(1) gt mu_(2)) respectively. Find (a) common acceleration of the blocks and (b) the contact force between the blocks.