Light of wavelength `lambda` strikes a photo - sensitive surface and electrons are ejected with kinetic energy is to be increased to `2 E` , the wavelength must be changed to `lambda'` where

Light of wavelength lamda strikes a photoelectric surface and electrons are ejected with kinetic energy K. If K is to be increased to exactly twice its original value, the wavelength must be changed to lamda' such that

Light of frequency v_0 strikes on a metal surface and electrons are ejected with kinetic energy E . If the kinetic energy is to be increased to twice of the given value , the wavelength must be changed to lamda' . which is equal to

If light of wavelength lambda_(1) is allowed to fall on a metal , then kinetic energy of photoelectrons emitted is E_(1) . If wavelength of light changes to lambda_(2) then kinetic energy of electrons changes to E_(2) . Then work function of the metal is

A beam of light of wavelength lambda and with illumination L falls on a clean surface of sodium . If N photoelectrons are emitted each with kinetic energy E , then

The de - Broglie wavelength lambda associated with an electron having kinetic energy E is given by the expression

How fast must an electron move to have a kinetic energy equal to the photon energy of sodium light at wavelength 500 nm?

How fast must an electron move to have a kinetic energy equal to the photon energy of sodium light at wavelength 588 nm?