In the reaction \(2NaOH+H_{3}PO_{4}\rightarrow Na_{2}HPO_{4}+2H_{2}O\) ,the equivalent weight of phosphoric acid \(H_{3}PO_{4}\) is

The equivalent weight of phosphoric acid (H_3 PO_4 ) in the reaction

Consider the following equation Ca(OH)_(2)+H_(3)PO_(4) rarr CaHPO_(4)+2H_(2)O The equivalent mass of phosphoric acid (H_(3)PO_(4)) is

A: In the reaction 2NaOH + H_(3)PO_(4) to Na_(2)HPO_(4) + 2H_(2)O equivalent weight of H_(3)PO_(4) is (M)/(2) where M is its molecular weight. R: "Equivalent weight"= ("molecular weight")/("n-factor")

In the reaction, H_3PO_4+Ca(OH)_2rarrCaHPO_4+2H_2O, the equivalent mass of H_3PO_4 is

H_(2)SO_(4)+2NaOH rarr Na_(2)SO_(4) +2H_(2)O In this equation the equivalent weight of sulphuric acid is..........

STATEMENT-1 : In the given reaction, NaOH+H_(3)PO_(4)rarr NaH_(2)PO_(4)+H_(2)O equivalent mass of H_(3)PO_(4) is M//3 STATEMENT-2 : H_(3)PO_(4) is tribasic acid.

In the reaction CA(OH)_(2)+H_(3)PO_(4) rarr Ca_(3)(PO_(4))_(2)+H_(2)O , the equivalent mass of H_(2) O is: (M molecular mass)