Home
Class 12
CHEMISTRY
Oleum is: H2S2O7, H2S2O6, H4S2O7, H3S2O7...

Oleum is: `H_2S_2O_7`, `H_2S_2O_6`, `H_4S_2O_7`, `H_3S_2O_7`.

A

`H_2S_2O_7`

B

`H_2S_2O_6`

C

`H_4S_2O_7`

D

`H_3S_2O_7`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    JMD PUBLICATION|Exercise EXAMPLE|105 Videos

Similar Questions

Explore conceptually related problems

Arrange the following in increasing order of property mentioned : Oxidation state of P : H_2PO_2, H_3PO_3, H_4P_2O_7,H_4P_2O_6

Arrange the following in increasing order of property mentioned : Oxidation state of S : H_2S_2O_8, H_2SO_3, H_2S_2O_3

Total number of dibasic acids among H_3PO_4, H_4P_2O_7, H_4P_2O_6, H_3PO_5, H_3PO_3, H_4P_2O_5, H_3PO_2 is

Draw the structure of H_2S_2O_7 .

Tollen's test is given by aldehydes: Ag^(+)+barerarrAg, E_(red)^@=+0.800V and C_6H_12O_6+H_2OrarrC_6H_12O_7+2H^++2bare, E_(ox)^@=-0.05V [Ag(NH_3)_2]+barerarrAg+2NH_3, E_(red)^@=+0.373V use (F)/(RT)=38.9 V^-1 Calculate(ln K) for C_6H_12O_6+2Ag^(+)+H_2OrarrC_2H_12O_7+2H^(+)+2Ag

Arrange the following in the decreasing order of property mentioned : H_2O, H_2S, H_2Se, H_2Te : Boiling point

Arrange the following in increasing order of property mentioned : Bond angle : H_2O, H_2S, H_2Te, H_2Se

Name the substance oxidised and substance reduced in the following reactions: 2H_2S +SO_2 rarr 2H_2O+3S