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If A=[{:(alpha,beta),(gamma,-alpha):}] i...

If `A=[{:(alpha,beta),(gamma,-alpha):}]` is such that `A^(2)=I`, then ……

A

`1+alpha^(2)+betagamma=0`

B

`1-alpha^(2)+betagamma=0`

C

`1-alpha^(2)-betagamma=0`

D

`1+alpha^(2)-betagamma=0`

Text Solution

Verified by Experts

The correct Answer is:
C
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