Home
Class 12
PHYSICS
The displacement of a chrage Q in the el...

The displacement of a chrage `Q` in the electric field
`E = e_(1)hati + e_(2)hatj + e_(3)hatk " is " vecr = ahati + bhatj`. The work done is

A

`Q(ae_(1)+be_(2))`

B

`Qsqrt((ae_(1))^(2)+(be_(2))^(2))`

C

`Q(e_(1)+e_(2))sqrt(a^(2)+b^(2))`

D

`Q(sqrt(e_(1)^(2)+e_(2)^(2)))(a+b)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    ERRORLESS |Exercise Ordinary Thinking Objective Questions (Electric Dipole)|38 Videos

  • ELECTROSTATICS

    ERRORLESS |Exercise Ordinary Thinking Objective Questions (Electric Flux and Gauss.s Law)|28 Videos

  • ELECTROSTATICS

    ERRORLESS |Exercise Ordinary Thinking Objective Questions (Electric Flux and Gauss.s Law)|28 Videos

  • ELECTRONICS

    ERRORLESS |Exercise Selv Evaluation Test|23 Videos

  • HEATING AND CHEMICAL EFFECT OF CURRENT

    ERRORLESS |Exercise Self Evaluation Test|14 Videos

Similar Questions

Explore conceptually related problems

The displacement of a charge Q in the electric field vec(E) = e_(1)hat(i) + e_(2)hat(j) + e_(3) hat(k) is vec(r) = a hat(i) + b hat(j) . The work done is

Charge Q is given a displacement r=ahati+bhatj in electric field E=E_1hati+E_2hatj . The work done is

Charge Q is given a displacement vec r = a hat i + b hat j in an electric field vec E = E_1 hat i + E_2 hat j . The work done is.

Charge Q is given by the displacement r=a hati+bhat j in an electrif field E=E_(1)hati+E_(2)hatj . The work done is

A particle of charge q, mass starts moving from origin under the action of an electric field vecE=E_(0)hati and magnetic field vecB=B_(0)hatk . Its velocity at (x,0,0) is v_(0)(6hati+8hatj) . The value of is

The line of intersection of the planes vecr . (3 hati - hatj + hatk) =1 and vecr. (hati+ 4 hatj -2 hatk)=2 is:

If force (vecF)=4hati+4hatj and displacement (vecs)=3hati+6hatk then the work done is

The angle between the planes vecr. (2 hati - 3 hatj + hatk) =1 and vecr. (hati - hatj) =4 is

A particle is acted upon by constant forces 4hati +hatj - 3hatk and 3hati + hatj -hatk which displace it from a point hati + 2hatj + 3hatk to the point 5hati + 4hatj + hatk . The work done in standard units by the forces is given by:

ERRORLESS -ELECTROSTATICS -Ordinary Thinking Objective Questions (Electric Field and Potential)
  1. Two positive point charges of 12 mu C and 8 mu C are 10 cm apart. The ...

    Text Solution

    |

  2. Three identical points charges, as shown are placed at the vertices of...

    Text Solution

    |

  3. The displacement of a chrage Q in the electric field E = e(1)hati + ...

    Text Solution

    |

  4. The potential at a point, due to a positive charge of 100 mu C at a di...

    Text Solution

    |

  5. A non-conducting solid sphere of radius R is uniformly charged. The ma...

    Text Solution

    |

  6. Two charges +5mu C and +10 mu C are placed 20 cm apart. The net electr...

    Text Solution

    |

  7. Which of the following is deflected by electric field ?

    Text Solution

    |

  8. As shown in the figure, charges and are placed at the vertices a...

    Text Solution

    |

  9. Consider the points lying on a straight line joining two fixed opposit...

    Text Solution

    |

  10. A charged particle of mass 5 xx 10^(-5) kg is held stationary in space...

    Text Solution

    |

  11. Three charges Q, +q and +q are placed at the vertices of a right-angle...

    Text Solution

    |

  12. Two electric charges 12 mu C and -6 mu C are placed 20 cm apart in air...

    Text Solution

    |

  13. In the given figure distance of the point from A where the electric fi...

    Text Solution

    |

  14. Figures below show regular hexagons, with charges at the vertices. In ...

    Text Solution

    |

  15. An electron is moving towards x-axis. An electric field is along y-dir...

    Text Solution

    |

  16. An electron enters in an electric field with its velocity in the direc...

    Text Solution

    |

  17. An electron of mass m and charge e is accelerated from rest through a ...

    Text Solution

    |

  18. The radius of a soap bubble whose potential is 16V is doubled. The new...

    Text Solution

    |

  19. The dimensions of 1/2 epsilon(0)E^(2) (epsilon(0)= permittivity of fre...

    Text Solution

    |

  20. In the rectangle, shown below, the two corners have charges q(1) = - 5...

    Text Solution

    |