Equation of chord of minimum length passing through `(1, 2)` of Circle `x^2+y^2-4x-2y-4=0` is `ax + by + c = 0` then `a + b + c = `

The least length of chord passing through (2,1) of the circle x^(2)+y^(2)-2x-4y-13=0 is

For the circle x^(2)+y^(2)-2x-6y+1=0 the chord of minimum length and passing through (1,2) is of length-

The minimum length of the chord of the circle x^(2)+y^(2)+2x+2y-7=0 which is passing (1,0) is :

The equation of the circle passing through (1/2, -1) and having pair of straight lines x^2 - y^2 + 3x + y + 2 = 0 as its two diameters is : (A) 4x^2 + 4y^2 + 12x - 4y - 15 = 0 (B) 4x^2 + 4y^2 + 15x + 4y - 12 = 0 (C) 4x^2 + 4y^2 - 4x + 8y + 5 = 0 (D) none of these

" The equation of smallest circle passing through intersection of curve " x^(2)+y^(2)-4x-2y-2=0 " and line " x+y-5=0 " is

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

If (2, -2),(-1,2), (3,5) are the vertices of a triangle then the equation of the side not passing through (2,-2) is (A) x + 2y +1 = 0 (B) 2x - y- 4= 0 (C) X-3y -3= 0 (D) 3x – 4y + 11 = 0

Find the equation of the circle passing through (-2,14) and concentric with the circle x^(2)+y^(2)-6x-4y-12=0