`int_0^pix/(1+cos^2x)dx=`

Evaluate: int_0^pi x/(1+cos^2x)dx

int_0^pi (cos^2x)dx ,

Evaluate: int_0^pi x/(a^2-cos^2x)dx

Evaluate int_0^(pi/2) cos^2x dx

Evaluate: int_0^pi(xsinx)/(1+cos^2x)dx

Evaluate: int_0^pix/(1+sinx)dx

(i) int_0^(pi/2) sin^2 x dx (ii) int_0^(pi//2) cos^2 x dx

If the value of int_0^pi(x/(1+sinx))^2dx=lambda , then find the value of the integral =int_0^pi[(2x^2*cos^2(x/2))/(1+sinx)^2]dx

Evaluate : int_0^(pi/4) ( cos 2 x)/( cos 2x + sin 2x) dx