`f (x)= max |2 sin y-x|` where `y in R` then determine the minimum value of `f (x).`

If f(x)=sin(2x)+5 then the minimum value of f(x) is

If f(x)=sin(2x)+5 then the minimum value of f(x) is

Let f(x)=max{|sin x|,|cos x|}AA x in R then minimum value of f(x) is

If f(x)=max(sin x,cos x) Vx e R. Then sum ofmaximum and minimum values of f(x) is M then find (1)/(M+(1)/(sqrt(2)))

If f(x+y)=f(x)f(y) and sum_(x=1)^(oo)f(x)=2,x,y in N , where N is the set of all natural numbers , then the value of (f(4))/(f(2)) is :

Consider a differentiable f:R to R for which f(1)=2 and f(x+y)=2^(x)f(y)+4^(y)f(x) AA x , y in R. The minimum value of f(x) is

Let y = f (x) such that xy = x+y +1, x in R-{1} and g (x) =x f (x) The minimum value of g (x) is:

If f(x+ y) = f(x) + f(y) for x, y in R and f(1) = 1, then find the value of lim_(x->0)(2^(f(tan x)-2^f(sin x)))/(x^2*f(sin x))