Photons of energy 1.5 eV and 2.5 eV are incident on a metal surface of work function 0.5 eV. What is the ratio of the maximum kinetic energy of the photoelectrons ?

The radiations of 1 eV and 2.5 eV are incident on a metal having a work function of 0.5 eV . The ratio of their maximum velocities is

Light of wavelength 2000Å is incident on a metal surface of work function 3.0 eV. Find the minimum and maximum kinetic energy of the photoelectrons.

A photon of energy 7 eV is incident on a metal surface having the work function of 3.75 eV. What is the stopping potential ?

Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV . The minimum kinetic energy of the emitted photo - electrons will be

Light of two different frequencies whose photons have energies 1eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum kinetic energy of emitted electrons will be:

Photons of energy 3.55 eV each are incident on a metal surface whose work function is 1.9 eV. What is the maximum K.E with which an electron is ejected form tis surface ?

Two radiation of photons energy 3eV and 4.5 eV successively illuminate a photosensitive metallic surface of work function 2.5 eV the ratio of the maximum speeds of the emitted electrons is :-

Two differenct photons of energies, 1 eV and 2.5 eV, fall on two identical metal plates having work function 0.5 eV, Then the ratio of maximum KE of the electrons emitted from the two surface is -

Two radiations of photons energies 1 eV and 2.5 eV, successively illuminate a photosensitive metallic surface of work function 0.5 eV. The ratio of the maximum speeds of the emitted electrons is