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In Delta ABC, ray BD bisects angleABC. A...

In `Delta ABC`, ray BD bisects `angleABC`. `A-D-C`, `side DEabs()side BC`, `A-E-B`,
then prove that `(AB)/(BC) = (AE)/(EB)`.

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The correct Answer is:
`therefore " " (AB)/(BC) = (AE)/(EB)`
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