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In the adjoining figure, BC is a diamete...

In the adjoining figure, BC is a diameter of the circle with centre M.
PA is a tangent at A from P, which is a point on line BC. AD `bot` BC
prove that `DP^(2)=BPxxCP-BDxxCD`

Answer

Step by step text solution for In the adjoining figure, BC is a diameter of the circle with centre M. PA is a tangent at A from P, which is a point on line BC. AD bot BC prove that DP^(2)=BPxxCP-BDxxCD by MATHS experts to help you in doubts & scoring excellent marks in Class 10 exams.

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