Home
Class 10
PHYSICS
The bulging of the earth at the equ...

The bulging of the earth at the equator and flattening at the poles is due to

Text Solution

Verified by Experts

The correct Answer is:
F

Due to its rotation , the earth is bulges at the equator and is flatter at the poles.
Promotional Banner

Similar Questions

Explore conceptually related problems

.Derive an expression for the gravitational acceleration on the earth's surface at a latitude lambda OR Explain the variation of acceleration due to gravity due to the rotational motion of the earth OR Explain the effect of latitude on the value of acceleration due to gravity

The mass of the moon is 1/81 of the earth but the gravitational pull is 1/6 of the earth. It is due to the fact that

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

A body is taken to a height of nR from the surface of the earth . The ratio of acceleration due to gravity on the surface to that at the altitude is

Let omega be the angular velocity of the earth's rotation about its axis. Assume that the acceleration due to gravity on the earth's surface has the same value at the equator and the poles. An object weighed at the equator gives the same reading as a reading taken at a depth d below earth's surface at a pole (dlt ltR) . the value of d is-

Consider a spherical planet which is rotating about its axis such that the speed of a point on its equator is 'v' and the effective acceleration due to gravity on the equator is 1/3 of its value at the poles. What is the escape velocity for the particle at the pole of this planet?

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

If the radius of the earth were to shrink by 1% its mass remaining the same, the acceleration due to gravity on the earth's surface would

Discuss the variation of g with depth and derive the necessary formula. OR Show that the gravitational acceleration due to the earth at a depth d from its surface is g_d= g[1- frac(d)(R)] , where R is the radius of the earth and g is the gravitional acceleration at the earth's surface. OR Discus the variation of acceleration due to gravity with depth 'd' below the surface of the earth OR Derive an expression for acceleration due to gravity at depth 'd' below the surface of earth

Complete the aology: Shape of the Earth at equator:Bulged: : Shape of the Earth at Poles:_____