Home
Class 10
PHYSICS
Find the escape speed of a body from the...

Find the escape speed of a body from the surface of mars . [Radius of mars = 3392 Km, `g_(Mars) = 3.724 m//s^2` ]

Text Solution

Verified by Experts

`5.026xx10^3 ms^(-1)`
Promotional Banner

Similar Questions

Explore conceptually related problems

0n which factors does the escape speed of a body from the surface of the earth depend?

Escape velocity of a body from the surface of a spherical planet of mass M, radius R and density p is

Show that the escape velocity of a body from the surface of a planet of radius R and mean density rho is Rfrac(sqrt8pirhoG)(3) OR Show that the escape velocity of a body from the surface of the earth is 2Rfrac(sqrt2pirhoG)(3) , where R is the radius of the earth and rho is the mean density of the earth. OR Obtain formula of escape velocity of a body at rest on the earth's surface in terms of mean density of erth.

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 xx 10^3 km and its mass is 6.4 xx 10^23 kg.

Solve the following examples / numerical problems: Find the escape velocity of a body from the earth. [R_(earth)= 6.4xx10^6 m, rho_(earth)= 5.52xx10^3 kg/m^3,G=6.67xx10^-11 N-m^2/kg^2]

The escape velocity of a body from the surface of the earth is 11.2 km//s . If a satellite were to orbit close to the earth's surface, what would be its critical velocity?

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .

Solve the following examples / numerical problems: Find the escape velocity of a body from the earth. [M_(earth)= 6xx10^24 kg, R_(earth)=6.4xx10^6m,G=6.67xx10^-11 N-m^2/kg^2]

The escape velocity of a body from the earth's surface is 11.2km//s . The mass of the moon is (1//81)^(th) of that of earth. The radius of the moon is (1//3.7)^(th) that of earth . Find the escape velocity from moon's surface .

A body weighs 63 kg-wt on the surface of earth. Its weight on the surface of Mars will be (Mass of Mars = 1/9 mass of earth, Radius of 9 Mars = 1/2 Radius of earth)