Suppose the satellite is revolving at a height of 35780 km above the earth's surface with velocity 3.08 km/s . How much time the satellite will take to complete one revolution around the earth ?

Explanation

Assume that the satellite completes one revolution in time T seconds . During this period the distance travelled by the satellite wil be equal to circumfernce of the orbit . Assuming the radius by the satellite will be `2pir` .
Here , velocity `(v_(c))=("distance")/("time")`
`=(2pir)/(T)`
`therefore "Time period" T=(2pir)/(v_(c))`
As , r = R+h ,
`thereforeT=(2pi(R+h))/(v_(c))=(2xx3.14xx(6400+35780))/(3.08)`
= `(2xx3.14xx42180)/(3.08)`
=`(84360xx3.14)/(3.08)`
= 86003.38 s
=23.89 hrs
`~~` 23 hrs 53 min
The satellite will complete one revolution around the earth 23 hrs 53 min.