Suppose the orbit of a satellite is exactly 35780 km above the earth's surface. Determine the tangential velocity of the satellite `(G=6.67xx10^(-11) Nm^2//kg^2,` mass of the earth=`6xx10^(24)` kg, Radius of the earth =`6.4xx10^6m`)

Suppose the orbit of a satellite is exatly 35780 km above the earth's surface. Determine the tangential velocity of the satellite.

If the orbit of a satellite is exactly 35780 km above the earth's surface then tangential velocity of the satellite is 3.08 km/s. how much time the satellite will take to complete one revolution around the earth?

A satellite is orbiting the earth at a height of 20000 km from the surface of the earth . Determine the tangential velocity of the satellite.

Complete the aology: 6xx10^24kg: mass of the Earth: : 6.4xx10^6 m______.

Suppose the satellite is revolving at a height of 35780 km above the earth's surface with velocity 3.08 km/s . How much time the satellite will take to complete one revolution around the earth ?

The gravitational force of attraction between Earth and Venus, if the distance between them is 2.5xx10^(7) km, is [mass of Venus = 4.8xx1^(24) kg, mass of the Earth =6xx10^(24) kg

Determine the binding energy of satellite of mass1000 kg revolving in a circular orbit around the earth. Hence, find kinetic energy and potential energy of the satellite,[mass of earth = 6 xlO^24 kg, radius of earth = 6400 km, gravitational constant G = 6.67 xlO^-11 Nm^2//kg^2 ]

Determine the escape velocity of a planet with mass 3xx10^(25)"kg and radius" 9xx10^(6)m.

The mean radius of a planet is 6.67xx10^(3) km. The acceleration due to gravity on its surface is 10 m//s^(2) . If G = 6.67xx10^(-11)Nm^(2)//kg^(2) , then the mass of the planet will be [R=6.67xx10^(6)m]

A satellite is revolving around the orbit with a tangential velocity of 6.4 km/s . Determine the radius of the orbit of the satellite.