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Let barx be the mean of x(1), x(2), ………,...

Let `barx` be the mean of `x_(1), x_(2), ………, x_(n)` and `bary` be the mean of `y_(1), y_(2),……….,y_(n)`. If `barz` is the mean of `x_(1), x_(2), ……………..x_(n), y_(1), y_(2), …………,y_(n)`, then `barz` is equal to

Text Solution

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The correct Answer is:
`(barx +bary)/(2)`
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